-5x^-1=-4x^2

Solution for -5x^-1=-4x^2 equation:

-5x^-1=-4x^2

We move all terms to the left:

-5x^-1-(-4x^2)=0

We add all the numbers together, and all the variables

-(-4x^2)-5x-1=0

We get rid of parentheses

4x^2-5x-1=0

a = 4; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·4·(-1)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{41}}{2*4}=\frac{5-\sqrt{41}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{41}}{2*4}=\frac{5+\sqrt{41}}{8}
$